AB and CD are two identical rods each of length l and mass m by Seekh Raha Hoon

AB and CD are two identical rods each of length l and mass m joined to form a cross is fixed inside a ring by Seekh Raha Hoon

AB and CD are two identical rods each of length l and mass m joined to form a cross is fixed inside a ring of mass m and radius l/2. Moment of inertia of the system about a bisector of the angle between the rods (XY) is

Hint:
To solve this question, we need to find out the moment of inertia of the system about the axis passing through the centre and perpendicular to the plane. We have to use the perpendicular axis theorem for this purpose. Then again using the perpendicular axis theorem and symmetry, we can find out the final value of the moment of inertia about the given axis.

Q1
AB and CD are two identical rods each of length l and mass m joined to from a cross is fixed inside a ring of mass m and radius l/2. Moment of intertia of the system about a bisector of the angle between the rods (xy) is

Q2
Two identical rods each of mass 'M' and length 'l' are joined in crossed position. The moment of inertia of this system about a bisector is.

Q3
Two uniform identical rods each of mass M and length l are joined to form a cross as shown in figure. Find the moment of inertia of the cross about a bisector as shown dotted in the figure.

Q4
Two uniform thin identical rods AB and CD each of mass M and length L are joined so as are joined at middle so as to form a cross as shown , the moment of inertia of the cross about a bisector line EF is

Search Query
A uniform rod AB of length l and mass m is free to rotate about point A
Two rods each of mass m and length l are joined at the centre to form a cross
Two identical rods of mass M and length L are lying in a horizontal plane at an angle alpha
Two identical rods each of mass m and length l are joined at one end and free to rotate